A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking lot is 0.039 square mile. find the length and width of the parking lot.
Accepted Solution
A:
Let x----------> the length of the parking lot y----------> the width of the parking lot
we know that x=0.17+y-------->equation 1 0.039 mi²=x*y---------> equation 2
substitute 1 in 2 0.039=[0.17+y]*y----------> 0.039=0.17y+y²-----> y²+0.17y-0.039=0
using a graph tool-----> to resolve the second order equation see the attached figure
the solution is y=0.13 mi x=0.17+y------> x=0.17+0.13------> x=0.30 mi
the answer is the length of the parking lot is 0.30 miles the width of the parking lot is 0.13 miles