MATH SOLVE

3 months ago

Q:
# A spinner is divided into four equal sections labeled 1, 2, 3, and 4. Another spinner is divided into three equal sections labeled A, B, and C. Simon will spin each spinner one time. How many of the possible outcomes have an even number or a B?

Accepted Solution

A:

Since we are asked to compute the probability of two event with "or"

statement, then we will add the probabilities like this:

Denote A the first event and B the second event:

[tex]P(A\cup B)=P(A)+P(B)[/tex]

A="Get an even number":

[tex]P(A)= \frac{2}{4}= \frac{1}{2} [/tex]

B="Get section B":

[tex]P(B)= \frac{1}{3} [/tex]

Conclusion:

[tex]P(A\cup B)=P(A)+P(B)= \frac{1}{2} +\frac{1}{3}\\=\frac{5}{6}[/tex]

The probability is 5/6

statement, then we will add the probabilities like this:

Denote A the first event and B the second event:

[tex]P(A\cup B)=P(A)+P(B)[/tex]

A="Get an even number":

[tex]P(A)= \frac{2}{4}= \frac{1}{2} [/tex]

B="Get section B":

[tex]P(B)= \frac{1}{3} [/tex]

Conclusion:

[tex]P(A\cup B)=P(A)+P(B)= \frac{1}{2} +\frac{1}{3}\\=\frac{5}{6}[/tex]

The probability is 5/6