According to the label, a can of soup holds an average of 307 grams, with a standard deviation of 4.1 grams. Assuming a normal distribution, what is the probability that a can will be sold that holds more than 308 grams?
Accepted Solution
A:
Answer: 0.4052Step-by-step explanation:Given : Mean : [tex]\mu=\text{307 grams}[/tex]Standard deviation : [tex]\sigma = \text{4.1 grams}[/tex]The formula for z -score :[tex]z=\dfrac{x-\mu}{\sigma}[/tex]For x=308 , [tex]z=\dfrac{308-307}{4.1}=0.24390\approx0.24[/tex]The p-value = [tex]P(z>0.24)=1-P(z<0.24)[/tex][tex]=1-0.5948348= 0.4051652\approx0.4052[/tex]Hence, the probability that a can will be sold that holds more than 308 grams =0.4052.