If you are given the graph of h(x)=log(6)x, how could you graph m(x)=log(6)(x+3)? Translate each point of the graph of h(x) 3 units up. Translate each point of the graph of h(x) 3 units down. Translate each point of the graph of h(x) 3 units right. Translate each point of the graph of h(x) 3 units left.

Answer: Last option: Translate each point of the graph of h(x) 3 units left.Step-by-step explanation: There are some transformations for a function f(x). The following is one of these transformations: If [tex]f(x+k)[/tex], then the function is shifted "k" units to the left. Given the function  [tex]h(x)=log_6(x)[/tex] and the function  [tex]m(x)=log_6(x+3)[/tex], you can notice that the function m(x) is the function h(x) but shifted left 3 units. Therefore, you could graph the function m(x) by translating each point of the graph of the function h(x) 3 units left. This matches with the last option.