What is the x-intercept of the line containing the points (-6,10) and (12,-2)?

Answer:x = 9Step-by-step explanation:Given that,coordinate 1  = (-6,10)coordinate 2 = (12,-2)Step 1Find the slope of line which contain above coordinatesFormula to use [tex]m=\frac{y2 - y1}{x2-x1}[/tex] m = [tex]\frac{-2-10}{12+6}[/tex] m  = -2/3Step 2Find the equation of the lineFormula to usey = mx + cwhere m is the slope =  -2/3            c is the y intercept Using coordinate (-6,10) Plug in the formula10 = -2/3(-6) + c10 = 4 + cc = 10-4c = 6So, the equation will be y = -2/3x + 6Step 3Find the x-interceptwe know that the x-intercept is the value of x when the value of y is equal to zeroso substitute y with 0 in the equationwhen y = 00 = -2/3x + 62/3x = 6x = 6(3/2)x = 9