The equation shows a chemical reaction using 64 grams of calcium, 162 grams of zinc carbonate, and 152 grams of calcium carbonate.calcium + zinc carbonate → calcium carbonate + zincAccording to the law of conservation of matter, how much zinc is present in the product?Group of answer choices98 grams64 grams74 grams88 gramsFlag this QuestionQuestion 64.5 ptsTim dissolves 0.5 grams (g) of sugar in a beaker containing 50.0 g of water, as shown below.What is the mass of the solution?Group of answer choices45.5 g50.0 g50.5 g25.0 gFlag this QuestionQuestion 74.5 ptsIn her chemistry class, Carmen performed an experiment that involved a chemical reaction. She measured the total mass of the reactants she used in her experiment using a triple-beam balance. The measurement she obtained is illustrated below.ImageAccording to the law of conservation of mass, what was the mass of the products in her experiment?Group of answer choices342 g240 g243 g300 g
Accepted Solution
A:
[tex]\mathrm{Ca}+\mathrm{ZnCO}_3\Rightarrow\mathrm{CaCO}_3+\mathrm{Zn}[/tex]Zn and ZnCO_3 occur in a 1:1 ratio in this reaction. Zn has a molar mass of about 65.38 g/mol; C has a molar mass of 12.011 g/mol; and O has a molar mass of 15.999 g/mol. So ZnCO_3 has a total molar mass of about 125.4 g/mol. In this reaction,[tex](162\,\mathrm g\text{ ZnCO}_3)\left(\dfrac1{125.4}\dfrac{\rm mol}{\rm g}\right)=1.29\,\mathrm{mol}\text{ ZnCO}_3[/tex]are involved, so that about 1.29 moles of Zn are produced, which has a mass of[tex]1.29\,\mathrm{mol}\text{ Zn}\left(65.38\dfrac{\rm g}{\rm mol}\right)=84.3\,\mathrm g\text{ Zn}[/tex](round up to 88 g)###Masses add, so the total mass of the solution is 50.5 g###Hard to answer without the image...